欧美一级特黄大片做受成人-亚洲成人一区二区电影-激情熟女一区二区三区-日韩专区欧美专区国产专区

【Uva129】KryptonFactor(困難的串)-創(chuàng)新互聯(lián)

You have been employed by the organisers of a Super Krypton Factor Contest in which contestants
have very high mental and physical abilities. In one section of the contest the contestants are tested on
their ability to recall a sequenace of characters which has been read to them by the Quiz Master. Many
of the contestants are very good at recognising patterns. Therefore, in order to add some difficulty to
this test, the organisers have decided that sequences containing certain types of repeated subsequences
should not be used. However, they do not wish to remove all subsequences that are repeated, since in
that case no single character could be repeated. This in itself would make the problem too easy for the
contestants. Instead it is decided to eliminate all sequences containing an occurrence of two adjoining
identical subsequences. Sequences containing such an occurrence will be called “easy”. Other sequences
will be called “hard”.
For example, the sequence ABACBCBAD is easy, since it contains an adjoining repetition of the
subsequence CB. Other examples of easy sequences are:
? BB
? ABCDACABCAB
? ABCDABCD
Some examples of hard sequences are:
? D
? DC
? ABDAB
? CBABCBA
In order to provide the Quiz Master with a potentially unlimited source of questions you are asked
to write a program that will read input lines from standard input and will write to standard output.
Input
Each input line contains integers n and L (in that order), where n > 0 and L is in the range 1 ≤ L ≤ 26.
Input is terminated by a line containing two zeroes.
Output
For each input line prints out the n-th hard sequence (composed of letters drawn from the first L letters
in the alphabet), in increasing alphabetical order (Alphabetical ordering here corresponds to the normal
ordering encountered in a dictionary), followed (on the next line) by the length of that sequence. The
first sequence in this ordering is ‘A’. You may assume that for given n and L there do exist at least n
hard sequences.
As such a sequence is potentially very long, split it into groups of four (4) characters separated by
a space. If there are more than 16 such groups, please start a new line for the 17th group.
Your program may assume a maximum sequence length of 80.
For example, with L = 3, the first 7 hard sequences are:
A
AB
ABA
ABAC
ABACA
ABACAB
ABACABA
Sample Input
7 3
30 3
0 0
Sample Output
ABAC ABA
7
ABAC ABCA CBAB CABA CABC ACBA CABA
28

為商城等地區(qū)用戶提供了全套網(wǎng)頁設(shè)計制作服務(wù),及商城網(wǎng)站建設(shè)行業(yè)解決方案。主營業(yè)務(wù)為網(wǎng)站制作、成都網(wǎng)站設(shè)計、商城網(wǎng)站設(shè)計,以傳統(tǒng)方式定制建設(shè)網(wǎng)站,并提供域名空間備案等一條龍服務(wù),秉承以專業(yè)、用心的態(tài)度為用戶提供真誠的服務(wù)。我們深信只要達(dá)到每一位用戶的要求,就會得到認(rèn)可,從而選擇與我們長期合作。這樣,我們也可以走得更遠(yuǎn)!

大致的題意:就是你要輸入一個n和L,分別代表前L個字母輸出第n個小的困難的串,而困難的串就是其中沒有連續(xù)重復(fù)的字符串

利用的方法就是回溯法

#include<bits/stdc++.h>
using namespace std;
int S[100],cnt;
int n,L;

int dfs(int cur){
    //輸出當(dāng)前的hard sequence
    //判斷的條件是cnt為n 也就是第n個小的hard sequence
    if(cnt++==n){
        //cur是當(dāng)前坐標(biāo)長度
        for(int i=0;i<cur;i++){
            //注意格式
            printf("%c",'A'+S[i]);
            if(i%64==63 && i!=cur-1) printf("\n");
            else if(i%4==3 && i!=cur-1) printf(" ");

        }
        //輸出長度
        printf("\n%d\n",cur);
        return 0;
    }
    //接下來的內(nèi)容就是判斷當(dāng)前字符串是不是hard sequence
    for(int i=0;i<L;i++){
        S[cur]=i;
        int ok=1;
        for(int j=1;j*2<=cur+1;j++){ //后綴長度為j a(bcd)(bcd)
            //內(nèi)循環(huán)檢查 flag為equal
            //外循環(huán)檢查 flag為 ok
            int equal=1;
            for(int k=0;k<j;k++) if(S[cur-k]!=S[cur-k-j]) {equal=0;break;}
            if(equal) {ok=0;break;}
        }
        if(ok) if(!dfs(cur+1)) return 0;
    }
    return 1;
}

int main(){
   while(cin>>n>>L && (n!=0 && L!=0)){
        cnt=0;
        dfs(0);
    }
    return 0;
}

另外有需要云服務(wù)器可以了解下創(chuàng)新互聯(lián)scvps.cn,海內(nèi)外云服務(wù)器15元起步,三天無理由+7*72小時售后在線,公司持有idc許可證,提供“云服務(wù)器、裸金屬服務(wù)器、高防服務(wù)器、香港服務(wù)器、美國服務(wù)器、虛擬主機(jī)、免備案服務(wù)器”等云主機(jī)租用服務(wù)以及企業(yè)上云的綜合解決方案,具有“安全穩(wěn)定、簡單易用、服務(wù)可用性高、性價比高”等特點(diǎn)與優(yōu)勢,專為企業(yè)上云打造定制,能夠滿足用戶豐富、多元化的應(yīng)用場景需求。

網(wǎng)站名稱:【Uva129】KryptonFactor(困難的串)-創(chuàng)新互聯(lián)
鏈接URL:http://aaarwkj.com/article12/pgggc.html

成都網(wǎng)站建設(shè)公司_創(chuàng)新互聯(lián),為您提供定制開發(fā)、手機(jī)網(wǎng)站建設(shè)、網(wǎng)頁設(shè)計公司外貿(mào)建站、動態(tài)網(wǎng)站、服務(wù)器托管

廣告

聲明:本網(wǎng)站發(fā)布的內(nèi)容(圖片、視頻和文字)以用戶投稿、用戶轉(zhuǎn)載內(nèi)容為主,如果涉及侵權(quán)請盡快告知,我們將會在第一時間刪除。文章觀點(diǎn)不代表本網(wǎng)站立場,如需處理請聯(lián)系客服。電話:028-86922220;郵箱:631063699@qq.com。內(nèi)容未經(jīng)允許不得轉(zhuǎn)載,或轉(zhuǎn)載時需注明來源: 創(chuàng)新互聯(lián)

網(wǎng)站托管運(yùn)營
99久久中文字幕伊人| 四影虎影永久免费观看| 黄色录像一级二级三级| 99亚洲伊人久久精品影院| 97国产精品成人免费视频| 国产区精品福利在线熟女| 亚洲精品中文字幕码专区| 国产精品深夜在线观看| 国产精品精品久久久久久| 精品欧美熟妇高潮喷水特黄| 国产午夜18久久久| 国产三级国产精品国产国在线观看| 亚洲一区二区婷婷久久| 天天操天天干夜夜骑| 亚洲成人永久免费精品| 国产在线播放精品视频| 亚洲大陆免费在线视频| 欧美亚洲五月婷婷激情| 精品国产综合一区二区三区| 国产在线视频不卡福利片| 四虎最新永久在线网站| 久草手机福利在线观看| 欧美精品国产亚洲另类| 日韩欧美麻豆不卡一区二区| 久久成人a毛片免费观看网站| 日本激情精品在线观看| 国内一级黄色片免费观看| 国产自愉自愉免费精品七| 午夜夫妻生活视频在线观看| 国产av高清视频在线| 日韩一二三区免费不卡视频| 日本不卡的三区四区五区| 亚乱熟女一区二区三区| 亚洲综合中文字幕日韩| 久久久久久狠狠亚洲综合| av剧情网址在线观看| 中文免费在线观看av| 国产精品一区二区日韩新区| 国产精品一级性生活片| 色香蕉精品国产综合| 久久99久久久久久精品|